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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Electric Charges and Fields
Module - 1 Electrostatics
Duration: 9.07 Min
 
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Duration: 5.36 Min
 
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Duration: 3.27 Min
 
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Duration: 4.11 Min
 
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Duration: 4.01 Min
 
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Duration: 4.07 Min
 
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Module - 8 Coulomb's Law
Duration: 4.38 Min
 
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Duration: 10.25 Min
 
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Duration: 4.22 Min
 
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Module - 14 Solved Example-1
Duration: 3.41 Min
 
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Module - 15 Solved Example-2
Duration: 2.12 Min
 
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Module - 16 Solved Example-3
Duration: 5.01 Min
 
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Module - 17 Solved Example-4
Duration: 3.48 Min
 
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Module - 18 Solved Example-5
Duration: 3.30 Min
 
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Module - 19 Electric Field
Duration: 4.30 Min
 
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Duration: 7.26 Min
 
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Module - 22 Solved Example-6
Duration: 2.01 Min
 
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Module - 23 Solved Example-7
Duration: 2.32 Min
 
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Module - 24 Solved Example-8
Duration: 3.17 Min
 
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Module - 25 Solved Example-9
Duration: 1.54 Min
 
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Duration: 4.13 Min
 
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Duration: 5.03 Min
 
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Duration: 2.59 Min
 
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Duration: 1.51 Min
 
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Duration: 4.28 Min
 
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Duration: 5.14 Min
 
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Duration: 3.40 Min
 
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Duration: 4.06 Min
 
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Duration: 3.07 Min
 
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  1.  
  2. sir, sometimes it gets really hard for us to grasp what you have done like you directly put some figures while we still focusing on the concept then it appears and we don't understand it. at least make us know that we are doing or putting these values from there. thank you
    3 years ago by

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  3.  
  4. Sir, can u say is it important to mug up the final result of all these derivations .
    7 years ago by Prakash Raj

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  5.  
  6. Sir here u r integrating ring element from 0 to R. As EF at centre of ring is zero then why there is some EF at centre disc??? Why does expression comes out to be so??
    8 years ago by kunal sevkani
    Ans 1 ->
    this is because in case of a ring net magnitude of EF is zero as charges are present only around its circumference, but when a disc is taken a single ring is surrounded by other rings having charges present around it which doesn't let net EF be zero in a single ring.
    5 years ago by undefined

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